To find the counter balancing weight required for the crane beam to lift 1500kg and the total force going through to the boom, we use moments -
Equate the clockwise and anticlockwise moments:
(About C clockwise) - Xg x 1 = 55.2g x (1.5 - 1) + 1000g x 2
Xg = 27.6g + 2000g = 2027.6Kg mass required for balance
2027.6 x 9.8 = 19870.48N force required for balance
Equating the forces in a vertical direction:
R = Xg + 55.2g + 1000g = 2027.6g + 55.2g + 1000g = 3082.8Kg Mass
4582.8 x 9.8 = 30211.44N Force - Both of which is the total amount acting through to the boom.
Friday, 23 April 2010
Forces/Stress Calculation (i)
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